A) \[{{x}_{A}}=0.76;\,\,{{x}_{B}}=0.24\]
B) \[{{x}_{A}}=0.28;\,\,{{x}_{B}}=0.72\]
C) \[{{x}_{A}}=0.4;\,\,{{x}_{B}}=0.6\]
D) \[{{x}_{A}}=0.37;\,\,{{x}_{B}}=0.63\]
Correct Answer: B
Solution :
\[{{Y}_{A}}\,=\,\frac{{{P}_{A}}}{{{P}_{T}}}\,=\,\frac{{{P}^{O}}_{A}{{X}_{A}}}{{{P}^{O}}_{A}{{X}_{A}}+{{P}^{O}}_{B}{{X}_{B}}}\] \[=\frac{7\times {{10}^{3}}\times 0.4}{7\times {{10}^{3}}\times 0.4+12\times {{10}^{3}}\times 0.6}\] = 0.28 \[\therefore \,{{\,}_{Y}}_{B}\,\,=1-0.28=0.72\]You need to login to perform this action.
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