JEE Main & Advanced
JEE Main Paper (Held On 11-Jan-2019 Evening)
question_answer
The coordination number of Th in\[{{K}_{4}}[Th{{({{C}_{2}}{{O}_{4}})}_{4}}{{(O{{H}_{2}})}_{2}}]\]is \[({{C}_{2}}O_{4}^{2-}=oxalato)\]
[JEE Main Online Paper (Held on 11-jan-2019 Evening)]
A)8
B)10
C)14
D) 6
Correct Answer:
B
Solution :
Oxalato \[({{C}_{2}}O_{4}^{2-})\]is a bidentate and \[{{H}_{2}}O\]is unidentate ligand.