A) \[10\text{ }rad/{{s}^{2}}\]
B) \[\text{20 }rad/{{s}^{2}}\]
C) \[\text{12 }rad/{{s}^{2}}\]
D) \[\text{16 }rad/{{s}^{2}}\]
Correct Answer: D
Solution :
\[40+f=ma=m(R\alpha )\] ?(i) \[40\times R-f\times R=m{{R}^{2}}\alpha \] ?(ii) From eqn (i) and (ii),\[80=2mR\alpha \] \[\alpha =\frac{40}{mR}=\frac{40}{5\times 0.5}\]\[=16rad/{{s}^{2}}\]You need to login to perform this action.
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