A) \[{{6}^{5}}\times (15)!\]
B) \[(15)!\times 6!\]
C) \[{{5}^{6}}\times 15\]
D) \[5!\times 6!\]
Correct Answer: B
Solution :
Here, f(k)=multiple of 3(3,6,9,12,15,18) For k = 4, 8, 12, 16, 20 there are \[6\times 5\times 4\times 3\times 2=6!\]ways For rest numbers, there are 15! ways \[\therefore \]Total ways \[=6!(15!)\]You need to login to perform this action.
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