A) \[\{\pi \}\]
B) \[\left\{ 0 \right\}\]
C) \[\phi \](an empty set)
D) \[\{0,\pi \}\]
Correct Answer: C
Solution :
Here,\[f(x)=sin|x|-|x|+2(x-\pi )cos|x|\] \[\because \]\[\sin |x|-|x|\]is differentiable function at x = 0 \[\therefore \]\[K=\phi \](an empty set)You need to login to perform this action.
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