A) \[KI\]and\[KMn{{O}_{4}}\]
B) \[KI{{O}_{3}}\]and\[Mn{{O}_{2}}\]
C) \[KI\]and\[{{K}_{2}}Mn{{O}_{4}}\]
D) \[Mn{{O}_{2}}\]and\[KI{{O}_{3}}\]
Correct Answer: D
Solution :
\[\underset{(A)}{\mathop{2Mn{{O}_{2}}}}\,+4KOH+{{O}_{2}}\to \underset{Green\,(B)}{\mathop{2{{K}_{2}}Mn{{O}_{4}}}}\,+2{{H}_{2}}O\] \[3{{K}_{2}}Mn{{O}_{4}}+4HCl\to \underset{Purple\,(C)}{\mathop{2KMn{{O}_{4}}}}\,+Mn{{O}_{2}}+2{{H}_{2}}O\] \[2KMn{{O}_{4}}+{{H}_{2}}O+KI\to 2KOH+\underset{(A)}{\mathop{2Mn{{O}_{2}}}}\,+\underset{(D)}{\mathop{KI{{O}_{3}}}}\,\]You need to login to perform this action.
You will be redirected in
3 sec