(Speed of light\[=3\times {{10}^{8}}m/s\] |
Planck?s constant \[=6.63\times {{10}^{-34}}Js\] |
Mass of electron\[=9.1\times {{10}^{-31}}kg\]) |
A) \[1.7\times {{10}^{6}}m/s\]
B) \[1.8\times {{10}^{6}}m/s\]
C) \[1.45\times {{10}^{6}}m/s\]
D) \[1.1\times {{10}^{6}}m/s\]
Correct Answer: C
Solution :
The wavelength of photon of frequency v is \[\lambda =\frac{c}{\upsilon }\] ?(i) The de Broglie wavelength of the electron is \[{{\lambda }_{e}}=\frac{h}{mv}\] \[\Rightarrow \]\[v=\frac{h}{m{{\lambda }_{e}}}=\frac{h\upsilon }{mc\times {{10}^{-3}}}\] [Given\[{{\lambda }_{e}}={{10}^{-3}}\lambda \]] \[v=\frac{6.63\times {{10}^{-34}}\times 6\times {{10}^{14}}}{9.1\times {{10}^{-31}}\times 3\times {{10}^{8}}\times {{10}^{-3}}}\]\[=1.46\times {{10}^{6}}m/s\]You need to login to perform this action.
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