A) \[\frac{1}{{{n}^{2}}}\]
B) \[{{n}^{2}}\]
C) \[\frac{1}{n}\]
D) \[n\]
Correct Answer: C
Solution :
\[{{k}_{1}}=\frac{C}{{{\ell }_{1}}}\] \[{{k}_{2}}=\frac{C}{{{\ell }_{2}}}\] \[\frac{{{k}_{1}}}{{{k}_{2}}}=\frac{C{{\ell }_{2}}}{{{\ell }_{1}}C}{{\ell }_{2}}=\frac{{{\ell }_{2}}}{n{{\ell }_{2}}}=\frac{1}{n}\]You need to login to perform this action.
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