A) 2.5 mA
B) 3.5 Ma
C) 7.5 mA
D) 1.5 mA
Correct Answer: B
Solution :
Maximum current will flow from zener if input voltage is maximum. When zener diode works in breakdown state, voltage across the zener will remain same. \[\therefore \]\[{{V}_{across4k\Omega }}=64\] \[\therefore \]Current through\[4K\Omega =\frac{6}{4000}A=\frac{6}{4}mA\] Since input voltage = 16V \[\therefore \]Potential difference across \[2K\Omega =10V\] \[\therefore \] Current through \[2k\Omega =\frac{10}{2000}=5mA\] \[\therefore \] Current through zener diode \[=({{I}_{S}}-{{I}_{L}})=3.5mA\]You need to login to perform this action.
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