[Specific heat of water \[=4200\text{ }J/kg\text{ }{}^\text{o}C\]), |
Latent heat of water = 2260 kJ/kg] |
A) 3 minutes
B) 22 minutes
C) 10 minutes
D) 16 minutes
Correct Answer: B
Solution :
\[Q=P\times t\] \[Q=mc\Delta T+mL\] \[P=\frac{V_{rms}^{2}}{R}\] \[4200\times 80+2260\times {{10}^{3}}=\frac{{{(200)}^{2}}}{20}\times t\] \[t=1298\text{ }sec\] \[t\simeq 22\min \]You need to login to perform this action.
You will be redirected in
3 sec