A) \[\left( g\sqrt{3} \right)/r\]
B) \[\frac{\sqrt{3}g}{2r}\]
C) \[2g/r\]
D) \[2g/\left( r\sqrt{3} \right)\]
Correct Answer: D
Solution :
\[N\sin \theta =m\frac{r}{2}{{\omega }^{2}}\] ?.(1) \[N\cos \theta =mg\] ?.(2) \[\tan \theta =\frac{r{{\omega }^{2}}}{2g}\] \[\frac{r}{2\frac{\sqrt{3}r}{2}}=\frac{r{{\omega }^{2}}}{2g}\] \[{{\omega }^{2}}=\frac{2g}{\sqrt{3}r}\]You need to login to perform this action.
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