A) \[5.4\mu C\]
B) \[24\mu C\]
C) \[13.4\mu C\]
D) \[9.6\mu C\]
Correct Answer: B
Solution :
So total charge flow \[=q=5.4\mu F\times 10V\] \[=54\mu C\] The charge will be distributed in the ratio of capacitance \[\Rightarrow \frac{{{q}_{1}}}{{{q}_{2}}}=\frac{2.4}{3}=\frac{4}{5}\] \[\therefore \]\[9X=54\mu C\Rightarrow X=6\mu C\] \[\therefore \]charge on \[4\mu F\]capacitor will be \[=4X=4\times 6\mu C\] \[=24\mu C\]You need to login to perform this action.
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