A) n = 5
B) n = 4
C) n = 6
D) n = 7
Correct Answer: A
Solution :
\[\frac{1}{\lambda }=R\left( \frac{1}{{{m}^{2}}}-\frac{1}{{{n}^{2}}} \right){{z}^{2}}\] \[\frac{1}{1085}=R\left( \frac{1}{{{m}^{2}}}-\frac{1}{{{n}^{2}}} \right){{2}^{2}}\] \[\frac{1}{304}=R\left( \frac{1}{{{1}^{2}}}-\frac{1}{{{m}^{2}}} \right){{2}^{2}}\] \[\therefore m=2\] \[\therefore n=5\]You need to login to perform this action.
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