A) \[\frac{8}{3}\]
B) \[\frac{10}{3}\]
C) \[6\]
D) \[-\frac{2}{3}\]
Correct Answer: C
Solution :
\[\{(x,y):{{y}^{2}}\le 4x,x+y\le 1,x\ge 0,y\ge 0\}\] \[A\int\limits_{0}^{3-2\sqrt{2}}{2\sqrt{x}dx}+\frac{1}{2}\left( 1-\left( 3-2\sqrt{2} \right) \right)\left( 1-(3-2\sqrt{2}) \right)\] \[=\frac{2[{{x}^{3/2}}]_{0}^{3-2\sqrt{2}}}{3/2}+\frac{1}{2}\left( 2\sqrt{2}-2 \right)\left( 2\sqrt{2}-2 \right)\] \[=\frac{8\sqrt{2}}{3}+\left( -\frac{10}{3} \right)\] \[a=\frac{8}{3},b=-\frac{10}{3}\] \[a-b=6\]You need to login to perform this action.
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