A) 2.85
B) 11.4
C) 5.7
D) 22.8
Correct Answer: D
Solution :
\[{{I}_{2(s)}}\to {{I}_{2(g)}}:\Delta {{H}_{1}}=24cal/g\,\text{at}\,\text{20}{{\text{0}}^{o}}C\] \[\Delta {{H}_{2}}=\Delta {{H}_{1}}+\Delta {{C}_{{{P}_{rxn}}}}({{T}_{2}}-{{T}_{1}})\] \[=24+\left( 0.0310.055 \right)\times 50\] \[=241.2\] \[=22.8\text{ }Cal/g\]You need to login to perform this action.
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