A) \[8.85\times {{10}^{-10}}C\]
B) \[7.85\times {{10}^{-10}}C\]
C) \[9.85\times {{10}^{-10}}C\]
D) \[6.85\times {{10}^{-10}}C\]
Correct Answer: A
Solution :
The electric field between two plates is \[E=\frac{\sigma }{{{\varepsilon }_{0}}}=\frac{q}{A{{\varepsilon }_{0}}}\Rightarrow q=EA{{\varepsilon }_{0}}\] \[=(100)(1)(8.85\times {{10}^{-12}})\] \[q=8.85\times {{10}^{-10}}C\]You need to login to perform this action.
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