A) \[\frac{4\upsilon }{3}\]
B) \[2\upsilon \]
C) \[\frac{5\upsilon }{3}\]
D) \[\frac{3\upsilon }{2}\]
Correct Answer: D
Solution :
Einstein?s photoelectric equation in the two cases is given by \[\frac{e{{V}_{0}}}{2}=h\upsilon -h{{\upsilon }_{0}}\] ...(i) and\[e{{V}_{0}}=\frac{h\upsilon }{2}-h{{\upsilon }_{0}}\] ?(ii) From eqn. (i) and (ii), \[\frac{1}{2}=\frac{h\upsilon -h{{\upsilon }_{0}}}{h\upsilon /2-h{{\upsilon }_{0}}}\Rightarrow {{\upsilon }_{0}}=\frac{3}{2}\upsilon \]You need to login to perform this action.
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