A) \[-\omega ({{R}_{1}}+{{R}_{2}})\hat{i}\]
B) \[\omega ({{R}_{1}}-{{R}_{2}})\hat{i}\]
C) \[\omega ({{R}_{2}}-{{R}_{1}})\hat{i}\]
D) \[-\omega ({{R}_{1}}+{{R}_{2}})\hat{i}\]
Correct Answer: C
Solution :
The angle transversed in time \[\frac{\pi }{2\omega }\]is\[\theta =\omega t=\frac{\omega \pi }{2\omega }=\frac{\pi }{2}\]i.e., at\[t=\frac{\pi }{2\omega },\]the position of two particles is shown in the figure \[\therefore \] The relative velocity\[{{\vec{v}}_{A}}-{{\vec{v}}_{B}}\]is \[=-{{R}_{1}}\omega \hat{i}-(-{{R}_{2}}\omega \hat{i})\] \[=\omega ({{R}_{2}}-{{R}_{1}})\hat{i}\]You need to login to perform this action.
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