A) 200 ohm
B) 6250 ohm
C) 6200 ohm
D) 250 ohm
Correct Answer: A
Solution :
The full scale deflection current \[{{I}_{g}}=25\times 4\times {{10}^{-4}}A\] Let R be the resistance connected \[{{I}_{g}}=\frac{V}{R+{{R}_{g}}}\Rightarrow 25\times 4\times {{10}^{-4}}=\frac{2.5}{R+50}\] \[\Rightarrow \]\[R=200\Omega \]You need to login to perform this action.
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