A)
B)
C)
D)
Correct Answer: B
Solution :
The moment of inertia I(x) at distance x is \[I(x)=\frac{2}{5}M{{R}^{2}}+M{{x}^{2}}\] \[{{x}^{2}}=\frac{1}{M}(I(x)-\frac{2}{5}M{{R}^{2}})\] This equation resembles the standard equation of parabola i.e., \[{{(x-h)}^{2}}=4p(y-k)\] Hence the curve will be parabolic.You need to login to perform this action.
You will be redirected in
3 sec