A) \[A=202;\text{ }Z=80\]
B) \[A=200;\text{ }Z=81\]
C) \[A=208;\text{ }Z=80\]
D) \[A=208;\text{ }Z=82\]
Correct Answer: D
Solution :
The mass number A of the end nucleus is \[232-\left( 6\times 4 \right)=208\] The atomic number Z of \[_{Z}^{A}X\]by conservation of charge is \[90-\left( 6\times 2-4\times 1 \right)=82\]You need to login to perform this action.
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