A) \[C{{H}_{3}}CH=C=C{{H}_{2}}\]
B) \[C{{H}_{3}}C{{H}_{2}}C\equiv CH\]
C) \[C{{H}_{3}}C{{H}_{2}}\underset{\begin{smallmatrix} | \\ N{{H}_{2}} \end{smallmatrix}}{\mathop{CH}}\,-\underset{\begin{smallmatrix} | \\ N{{H}_{2}} \end{smallmatrix}}{\mathop{C{{H}_{2}}}}\,\]
D) \[C{{H}_{3}}CH=CHC{{H}_{2}}N{{H}_{2}}\]
Correct Answer: B
Solution :
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