A) \[\bar{A}B\]
B) \[A\bar{B}\]
C) \[AB+\overline{AB}\]
D) \[A\overline{B}+\overline{A}B\]
Correct Answer: B
Solution :
\[Y=\overline{\overline{A.(\overline{AB})}.(\overline{AB}+B)}\] (by applying De Morgan theorem) \[Y=A.(\overline{A}+\overline{B})+(\overline{\overline{AB}}+\overline{B})\] \[Y=A.(\overline{A}+\overline{B})+(AB.\overline{B})\] \[(\because B.\overline{B}=0)\] \[Y=A.\overline{A}+A\overline{B},Y=A\overline{B}\]You need to login to perform this action.
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