A) \[\left( \frac{3}{2},\infty \right)\]
B) \[\left( 1,\frac{3}{2} \right)\]
C) \[\left( -\infty ,0 \right)\]
D) \[\left( 0,\frac{1}{2} \right)\]
Correct Answer: D
Solution :
Since, (1, a) lies between \[x+y=1\]and \[2(x+y)=3\] \[\therefore \]Put \[x=1\]in \[\text{2(x}+\text{y)}=\text{3}.\] We get the range of y. Thus, \[2(1+y)=3\Rightarrow y=\frac{3}{2}-1=\frac{1}{2}\] Thus ?a' lies in \[\left( 0,\frac{1}{2} \right)\]You need to login to perform this action.
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