A) 0
B) 1.5
C) 1
D) 2
Correct Answer: D
Solution :
\[A\xrightarrow[{}]{{}}B\] Initial concentration Rate of reaction \[2\times {{10}^{-3}}M\] \[2.40\times {{10}^{-4}}M{{s}^{-1}}\] \[1\times {{10}^{-3}}M\] \[0.60\times {{10}^{-4}}M{{s}^{-1}}\] rate of reaction\[r=k{{[A]}^{x}}\]where x = order of reaction hence \[2.40\times {{10}^{-4}}=k{{[2\times {{10}^{-3}}]}^{x}}\] .....(i) \[0.60\times {{10}^{-4}}=k{{[1\times {{10}^{-3}}]}^{x}}\] ....(ii) on dividing eqn.(i) from eqn. (ii) we get\[4={{(2)}^{x}}\] \[\therefore \]\[x=2\]i.e. order of reaction = 2You need to login to perform this action.
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