A) \[1.50\]
B) \[1.55\]
C) \[1.75\]
D) \[1.51\]
Correct Answer: B
Solution :
\[\frac{l}{F}=\frac{2}{f}+\frac{l}{{{f}_{m}}}\] \[{{f}_{m}}\Rightarrow \infty \] This gives, \[f=56\] \[{{f}_{m}}=\frac{R}{2}\backslash \] Hence \[\frac{1}{F}=\frac{2}{f}+\frac{2}{R}\] This gives, \[R=31.11\] \[\frac{1}{f}=(\mu -1)(\frac{1}{R})\] \[\mu =1.55\]You need to login to perform this action.
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