A) 0.5
B) 0.7
C) 0.3
D) 0.6
Correct Answer: D
Solution :
\[\text{3}\text{.5 rev/second}\] \[\text{1rev}\to \text{2}\pi \text{rad}\] \[3.5rev\to 2\pi \times 3.5rad\] \[\Rightarrow w=7\pi rad/\sec \] \[\mu mg=\frac{m{{v}^{2}}}{1.25}\] \[\mu mg=\frac{m{{(rw)}^{2}}}{r}\] \[\mu mg=mr{{w}^{2}}\] \[\mu =\frac{r{{w}^{2}}}{g}=\frac{1.25\times {{10}^{-2}}\times {{\left( 7\times \frac{22}{7} \right)}^{2}}}{10}\] \[=\frac{1.25\times {{10}^{-2}}\times {{22}^{2}}}{10}\] \[=0.6\]You need to login to perform this action.
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