A) \[1:2\]
B) \[1:4\]
C) \[1:3\]
D) \[1:5\]
Correct Answer: C
Solution :
We know that, the moment of inertia of the circular disk about the center is \[{{M}_{Z}}=\frac{M{{R}^{2}}}{2}\] Using parallel axis theorem, \[M_{Z}^{'}=\frac{M{{R}^{2}}}{2}+M{{R}^{2}}=\frac{3M{{R}^{2}}}{2}\] \[\frac{{{M}_{Z}}}{M_{Z}^{'}}=1/3\]
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