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JEE Main & Advanced JEE Main Paper (Held On 22 April 2013)

  • question_answer
    An ideal gas at atmospheric pressure is adiabatically compressed so that its density becomes 32 times of its initial value. If the final pressure of gas is 128 atmosphers, the value of \['\gamma '\] the gas is:     JEE Main  Online Paper (Held On 22 April 2013)

    A)  1.5                                        

    B)  1.4

    C)  1.3                                        

    D)  1.6

    Correct Answer: B

    Solution :

     Volume of the gas \[v=\frac{m}{d}\]and using \[P{{V}^{\gamma }}=\text{constant}\] \[\frac{P'}{P}=\frac{V}{V'}={{\left( \frac{d'}{d} \right)}^{\gamma }}\] or            \[128={{(32)}^{\gamma }}\] \[\therefore \]  \[\gamma =\frac{7}{5}=1.4\]


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