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JEE Main & Advanced JEE Main Online Paper (Held On 23 April 2013)

  • question_answer
    A system of four gates is set up as shown. The ?truth table? corresponding to this systemis:     JEE Main Online Paper ( Held On 23  April 2013 )

    A)
    A B Y
    0 0 1
    0 1 0
    1 0 0
    1 1 1
                      

    B)
    A B Y
    0 0 0
    0 1 0
    1 0 1
    1 1 0

    C)
    A B Y
    0 0 1
    0 1 0
    1 0 1
    1 1 0

    D)
    A B Y
    0 0 1
    0 1 1
    1 0 0
    1 1 0

    Correct Answer: A

    Solution :

                     In the given system all four gate is NOR gate Truth Table
    A B \[(y'=\overline{A+B})\] \[y''=(\overline{A+Y'})\] \[y'''=(A+y'')\] \[y=(\overline{y''+y'''})\]
    0 0 1 0 0 1
    0 1 0 1 0 0
    1 0 0 0 1 0
    1 1 0 0 0 1
    i.e.,
    A B Y
    0 0 1
    0 1 0
    1 0 0
    1 1 1


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