A) 4
B) 9.0
C) 10
D) 9.6
Correct Answer: D
Solution :
Given at 330 K \[{{K}_{w}}={{10}^{-13.6}}\] i.e.\[p{{K}_{w}}=pH+pOH\] \[\because \]\[pOH=-\log [O{{H}^{-}}]\] \[\text{13}.\text{6}=\text{pH}+\text{pOH}\] \[=-\log {{10}^{-4}}\] \[=pH+4\] \[=4\] \[\therefore \]\[pH=13.6-4\] \[=9.6\]You need to login to perform this action.
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