A) 3
B) 5
C) 4
D) 6
Correct Answer: A
Solution :
\[\sin 2x-2\cos x+4\sin x=4\] \[\Rightarrow \]\[2\sin x.\cos x-2\cos x+4\sin x-4=0\] \[\Rightarrow \]\[(\sin x-1)(\cos x-2)=0\] \[\because \]\[\cos x-2\ne 0,\therefore \sin x=1\] \[\therefore \]\[\frac{\pi }{2},\frac{5\pi }{2},\frac{9\pi }{2}\]You need to login to perform this action.
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