A) \[2\sqrt{2}\]
B) \[2\sqrt{2}-2\]
C) \[2\sqrt{2}+2\]
D) 0
Correct Answer: B
Solution :
\[y=|\cos x-\sin x|\] Required area\[=2\int\limits_{0}^{\pi /4}{(\cos x-\sin x)dx}\] \[=2[\sin x+\cos x]_{0}^{\pi /4}\] \[=2\left[ \frac{2}{\sqrt{2}}-1 \right]=(2\sqrt{2}-2)sq.\]unitsYou need to login to perform this action.
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