A) 1.75 mm
B) 2.0 mm
C) 1.50mm
D) 1.25 mm
Correct Answer: D
Solution :
\[{{Y}_{c}}\times (\Delta {{L}_{c}}/{{L}_{c}})={{Y}_{s}}\times (\Delta {{L}_{s}}/{{L}_{s}})\] \[\Rightarrow \]\[1{{\times }^{11}}\times \left( \frac{1\times {{10}^{-3}}}{1}=2\times {{10}^{11}} \right)\times \left( \frac{\Delta {{L}_{s}}}{0.5} \right)\] \[\therefore \]\[\Delta {{L}_{s}}=\frac{0.5\times {{10}^{-3}}}{2}=0.25mm\] Therefore, total extension of the composite wire\[=\Delta {{L}_{c}}+\Delta {{L}_{s}}\] \[=1\,mm+0.25m=1.25m\]You need to login to perform this action.
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