JEE Main & Advanced
JEE Main Online Paper (Held On 23 April 2013)
question_answer
If the time period \[t\] of the oscillation of a drop of liquid of density \[d\]radius \[r,\]vibrating under surface tension s is given by the formula \[t=\sqrt{{{r}^{2b}}{{s}^{c}}{{d}^{a/2}}.}\]It is observe that the time period is directly proportional to \[\sqrt{\frac{d}{s}.}\] The value of \[b\] should therefore be:
JEE Main Online Paper ( Held On 23 April 2013 )