A) \[\frac{{{\operatorname{K}}_{1}}{{\operatorname{K}}_{2}}}{{{\operatorname{K}}_{3}}}\]
B) \[\frac{{{\operatorname{K}}_{1}}\operatorname{K}_{3}^{2}}{{{\operatorname{K}}_{2}}}\]
C) \[{{\operatorname{K}}_{1}}{{\operatorname{K}}_{2}}{{\operatorname{K}}_{3}}\]
D) \[\frac{{{\operatorname{K}}_{2}}\operatorname{K}_{3}^{3}}{{{\operatorname{K}}_{1}}}\]
Correct Answer: D
Solution :
To calculate the-value of\[{{K}_{4}}\] in the given equation we should apply: eqn. (2) + eqn.(3) x 3-eqn. (1) hence \[{{K}_{4}}=\frac{{{K}_{2}}K_{3}^{3}}{{{K}_{1}}}\]You need to login to perform this action.
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