A) \[M{{n}^{2+}}<C{{l}^{-}}<C{{r}^{3+}}<Cr\]
B) \[M{{n}^{2+}}<C{{r}^{3}}^{-}<C{{l}^{-}}<Cr\]
C) \[C{{r}^{3+}}<C{{l}^{-}}<M{{n}^{2+}}<Cr\]
D) \[C{{r}^{3+}}<C{{l}^{-}}<Cr<M{{n}^{2}}^{+}\]
Correct Answer: A
Solution :
Lower the value of reduction potential higher will be reducing power hence the correct order will be\[M{{n}^{2+}}<C{{l}^{-}}<C{{r}^{3+}}<Cr\]
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