A) 18
B) 10
C) 5
D) 14
Correct Answer: D
Solution :
Since \[0<y<x<2y\] \[\therefore\] \[y>\frac{x}{2}\Rightarrow x-y<\frac{x}{2}\] \[\therefore\] \[x-y<y<x<2x+y\] Hence median \[=\frac{y+x}{2}=10\] \[\Rightarrow\] \[x+y=20\] ?(i) And range \[=(2x+y)-(x-y)=x+2y\] But range =28 \[\therefore\] \[x+2y=28\] ...(ii) From equations (i) and (ii), \[\therefore\] Mean \[=\frac{(x-y)+y+x+(2x+y)}{4}=\frac{4x+y}{4}\] \[=x+\frac{y}{4}=12+\frac{8}{4}=14\]You need to login to perform this action.
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