A) \[\frac{15}{16}{{I}_{0}}\]
B) \[\frac{3{{I}_{0}}}{4}\]
C) \[\frac{7}{8}{{I}_{0}}\]
D) \[\frac{31{{I}_{0}}}{32}\]
Correct Answer: A
Solution :
\[{{I}_{0}}=km{{l}^{2}}\] \[BC=l\] \[{{I}_{DEF}}=K\frac{m}{4}{{\left( \frac{l}{2} \right)}^{2}}\] \[=\frac{k}{16}m{{l}^{2}}\] \[{{I}_{DEF}}=\frac{{{I}_{0}}}{16}\] \[{{I}_{remain}}={{I}_{0}}=\frac{{{I}_{0}}}{16}\] \[=\frac{15{{I}_{0}}}{16}\]You need to login to perform this action.
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