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JEE Main & Advanced JEE Main Paper (Held On 8 April 2017)

  • question_answer
    There is a uniform electrostatic field in a region. The potential at various points on a small sphere centred at P, in the region, is found to vary between in limits 589.0V to 589.8 V. What is the potential at a point on the sphere whose radius vector makes an angle of \[60{}^\circ \] with the direction of the field? [JEE Online 08-04-2017]

    A)  589.4 V                               

    B)  589.5 V

    C)  589.2 V                               

    D)  589.6 V

    Correct Answer: A

    Solution :

    \[\Delta V=E.d\] 0.8 = Ed (max) \[\Delta V=Ed\cos \theta =0.8\times \cos 60\] = 0.4 589.4


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