A) 2
B) 5
C) 3
D) 1
Correct Answer: D
Solution :
Given, \[\frac{{{z}_{2}}}{{{z}_{1}}}\] is a purely imaginary i.e., \[ni\] Now, \[\left| \frac{2+3\frac{{{z}_{2}}}{{{z}_{1}}}}{2-3\frac{{{z}_{2}}}{{{z}_{1}}}} \right|=\left| \frac{2+3ni}{2-3ni} \right|=\frac{\sqrt{4+9{{n}^{2}}}}{4+9{{n}^{2}}}=1\]You need to login to perform this action.
You will be redirected in
3 sec