A) 2
B) 7
C) 5
D) 3
Correct Answer: A
Solution :
Let \[{{T}_{1}}\] and \[{{T}_{2}}\] be the time period of shorter length and larger length pendulums respectively. According to question, \[n{{T}_{1}}=(n-1){{T}_{2}}\] So, \[n2\pi =\sqrt{\frac{1}{g}}=(n-1)\,2\pi \sqrt{\frac{4}{g}}\] or \[n=(n-1)2\] \[n=2n-2\Rightarrow \,n=2\]You need to login to perform this action.
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