A) \[4.56\times {{10}^{-4}}\operatorname{M}{{\operatorname{s}}^{-1}}\]
B) \[1.14\times {{10}^{-2}}\operatorname{M}{{\operatorname{s}}^{-1}}\]
C) \[1.14\times {{10}^{-3}}\operatorname{M}{{\operatorname{s}}^{-1}}\]
D) \[5.7\times {{10}^{-3}}\operatorname{M}{{\operatorname{s}}^{-1}}\]
Correct Answer: B
Solution :
Rate of reaction \[=-\frac{1}{2}\,[Mn{{O}_{4}}^{-}]=\frac{1}{5}[{{l}_{2}}]\] \[\therefore \] Given, \[[MnO_{4}^{-}]=4.56\times {{10}^{-3}}\] \[\because \] Rate of appearance of \[{{l}_{2}}\] will be \[=\frac{5}{2}\times 4.56\times {{10}^{-3}}\] \[=11.4\times {{10}^{-3}}=1.14\times {{10}^{-2}}\,M{{s}^{-1}}\]You need to login to perform this action.
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