A) \[{{C}_{\operatorname{m}}}\left( \operatorname{t} \right)=A(1+\sin {{\omega }_{m}}t)\sin {{\omega }_{c}}t\]and 2
B) \[{{C}_{\operatorname{m}}}\left( \operatorname{t} \right)=A(1+\sin {{\omega }_{c}}t)\sin {{\omega }_{m}}t\]and 1
C) \[{{C}_{\operatorname{m}}}\left( \operatorname{t} \right)=A(1+\sin {{\omega }_{m}}t)\sin {{\omega }_{c}}t\]and 1
D) \[{{C}_{\operatorname{m}}}\left( \operatorname{t} \right)=A(1+\sin {{\omega }_{c}}t)\sin {{\omega }_{m}}t\]and 2
Correct Answer: A
Solution :
Modulation index \[=\frac{{{A}_{m}}}{{{A}_{c}}}=\frac{A}{A}=1\] Modulation signal will be As, \[{{C}_{m}}(t)=A(1+\sin {{\omega }_{m}}t)\sin {{\omega }_{c}}t\]You need to login to perform this action.
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