A) 92 m/s
B) 200 m/s
C) 100 m/s
D) 332 m/s
Correct Answer: B
Solution :
\[{{v}_{1}}=\frac{{{\omega }_{1}}}{{{k}_{1}}}=\frac{100\,\pi }{0.50\pi }=200\,m/s\] \[{{v}_{2}}=\frac{{{\omega }_{2}}}{{{k}_{2}}}=\frac{92\,\pi }{0.46\,\pi }=200\,m/s\] As, both the waves moves with the same speed, so the speed of resultant wave should be 200 m/s.You need to login to perform this action.
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