A) 8.25
B) 8.50
C) 9.00
D) 8.00
Correct Answer: C
Solution :
\[\sum\limits_{i=1}^{100}{xi=400}\] \[\sum\limits_{i=1}^{100}{x{{i}^{2}}\,=2475}\] variance \[{{3}^{2}}+{{4}^{2}}+{{5}^{2}}\] \[9+16+25=50\] \[=\frac{2475}{97}-\,{{\left( \frac{388}{97} \right)}^{2}}\] \[\frac{2425}{97}-16\] \[\frac{2425-1552}{97}=\frac{873}{97}\] = (9)You need to login to perform this action.
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