A) \[\frac{219{{R}^{2}}}{256}\,\]
B) \[\frac{237M{{R}^{2}}}{512}\]
C) \[\frac{197M{{R}^{2}}}{256}\,\]
D) \[\frac{19M{{R}^{2}}}{512}\]
Correct Answer: B
Solution :
\[{{I}_{D}}\,=\frac{m{{r}^{2}}}{2}\] \[{{I}_{removed}}\,=\frac{1}{2}\frac{m}{16}\,\frac{{{r}^{2}}}{16}+\frac{m}{16}\,\frac{9{{r}^{2}}}{16\,}(\operatorname{Im}+md)\] \[=\frac{m{{r}^{2}}+18m{{r}^{2}}}{512}\] \[=\frac{19m{{r}^{2}}}{512}\] \[{{I}_{remaining}}\,=\frac{m{{r}^{2}}}{2}-\frac{19}{512}\,m{{r}^{2}}\] \[=\frac{237}{512}\,m{{r}^{2}}\]You need to login to perform this action.
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