A) 0.2 m/s
B) 0.4 m/s
C) 2 m/s
D) 4 m/s
Correct Answer: C
Solution :
\[T\sin \theta \,=\frac{m{{v}^{2}}}{r}\] \[T\cos \theta \,=mg\] \[\tan \theta \,=\frac{{{v}^{2}}}{rg}\] \[\theta ={{45}^{\text{o}}}\] \[{{v}^{2}}=rg\] \[\upsilon =\sqrt{rg}\,=\sqrt{0.4\,\times 10}\] \[=2\,m/s\]You need to login to perform this action.
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