A) \[2\sqrt{14}\]
B) 6
C) \[\sqrt{53}\]
D) \[2\sqrt{21}\]
Correct Answer: A
Solution :
\[\frac{4}{2}=\frac{-y}{y+3}=\frac{10-z}{z-4}\] \[\Rightarrow \]\[z=6\And y=-2\] \[\Rightarrow \]\[R(4,-2,6)\] dist. from origin \[=\sqrt{16+4+36}=2\sqrt{14}\]You need to login to perform this action.
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