[A] | [B] |
[C] | [D] |
A) [A], [B], [C]
B) [A]
C) [A], [B], [D]
D) [B], [C]
Correct Answer: C
Solution :
Given initial velocity u=0 and acceleration is constant At time t \[v=0+at\,\Rightarrow v=at\] also \[x=0(t)+\frac{1}{2}a{{t}^{2}}\Rightarrow x=\frac{1}{2}a{{t}^{2}}\] Graph [a] ; [b] and [d] are correct.You need to login to perform this action.
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